3(x^2+4)=3x^2+12

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Solution for 3(x^2+4)=3x^2+12 equation:


Simplifying
3(x2 + 4) = 3x2 + 12

Reorder the terms:
3(4 + x2) = 3x2 + 12
(4 * 3 + x2 * 3) = 3x2 + 12
(12 + 3x2) = 3x2 + 12

Reorder the terms:
12 + 3x2 = 12 + 3x2

Add '-12' to each side of the equation.
12 + -12 + 3x2 = 12 + -12 + 3x2

Combine like terms: 12 + -12 = 0
0 + 3x2 = 12 + -12 + 3x2
3x2 = 12 + -12 + 3x2

Combine like terms: 12 + -12 = 0
3x2 = 0 + 3x2
3x2 = 3x2

Add '-3x2' to each side of the equation.
3x2 + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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